raiding math

[Panerai 1]

Three raiders go raiding one night. The GM charges thirty gold per raid for repairs. The raiders agree; and each pays ten gold. The raid lead takes them raiding. Later, the GM discovers s/he has overcharged them and asks the raid lead to return five gold to them. On the way to the elevator boss, the raid lead realizes that five gold can't be evenly split among three smart raiders, so he decides to keep two gold for himself (shaen is a greedy bastard) and return one gold to each raider.

At this point, the men have paid nine gold each, totaling 27. The raid lead has two, which adds up to 29. Where did the thirtieth gold piece go?

[ullariend]

Nothing happened to the gold, the claim that the raiders paid 9 is a red herring.

Each pays 10

So there is a pot of 30

RL takes 5 from the pot, gives one to each raider and keeps 2.

The result is 25 in the pot, 3 total with the raiders, and 2 with raid leader.

When you process the transaction this way, it adds up.


Alternatively, they each paid 2/3 to the RL 8 1/3 to the pot and kept 1, also adding up to 30.


Shaen's embezzlement of guild funds breaks the accuracy of calculating a net payment they way Pan does to get to 9 (I'm not sure if I could explain it further)